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This popular tutorial introduction to standard C++ has been completely updated, reorganized, and rewritten to help breset(pos) Turn off the bit in b at position pos programmers learn the language faster and use it in a more modern, effective wayJust as C++ has evolved since the last edition, so has the authors' approach to teaching it They now introduce the C++ standard library from the beginning, giving bflip() Change the state of each bit in b readers the means to write useful programs without first having to master every language detail Highlighting today's best practices, they show how to write programs that are safe, can be built quickly,in position outstanding performance bflip(pos) Reverse value of the bit in b and yet offer pos Examples that take advantage of the library, and explain the features of C++, also show how to make the best use of the bto_ulong() Returns an unsigned long fundamental C++ concepts and techniques makes language As in its previous editions, the book's authoritative discussion of with the same bits as inb it a valuable resource even for more experienced programmersProgram Faster and More Effectively with This Rewritten Classic Restructured for quicker learning, using the C++ standard library Updated to teach the most current programming os << b Prints the bits in b to the stream os styles and program design techniques Filled with new learning aids that emphasize important points, warn about common pitfalls, suggest good programming practices, and provide general usage tips Complete with exercises that reinforce skills learned Authoritative and comprehensive in its coverageThe source code for the book's extended examples is available on the Web at the address below

m m x(k) (i) = x(k) (iT0) is the ith IDFT sample given by Equation (10.45), NT = nf + Ncyclic is the length of the extended OFDM symbol, hk(n) is the sample of channel impulse response hk(t) sampled at t = nT0 - dk, and hk (n) = j 2pnWd k hk (n) exp . Note that the effect of fractional timing offset becomes nf a random phase term and can be incorporated into the random channel fading hk(n) to become hk(n) as long as dk is shorter than Ncyclic - Lp, where Lp is the number of signi cant multipaths in hk(t). Hence, the fractional timing offset appears as a linear phase shift at the output of the DFT and can be corrected by the channel equalizer, which does not distinguish the random phase introduced by the channel fading from those deriving from the timing offsets. Without loss of generality, consider the receive processing on user 1. To simplify the analysis, consider a hypothetical case where k = 0 and ek = 0 for all k = 1. Hence, we are interested to rst look at the situation where all the remaining users have been perfectly synchronized except for the rst user and try to understand the effect of frequency and timing offsets with respect to user 1. Collecting a block of nf received samples for DFT processing of the mth OFDM symbol, we have j 2p 1 mNT 1 y m = exp G ( 1 )D(m) (m 1 )h 1 nf j 2p k mNT + exp G( nf k 1

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Theany operation returns true if one or more bits of the bitset object are turned onthat is, are equal to 1 Conversely, the operation none returns true if all the bits of the object are set to zero

bitset<32> bitvec; // 32 bits, all zero bool is_set = bitvecany(); bool is_not_set = bitvecnone();

If we need to know how many bits are set, we can use the count operation, which returns the number of bits that are set:

(10.51)

The return type of the count operation is a library type named size_t The size_t type is defined in the cstddef header, which is the C++ version of the stddefh header from the C library It is a machine-specific unsigned type that is guaranteed to be large enough to hold the size of an object in memory Thesize operation, like the one in vector and string, returns the total number of bits in the bitset The value returned has type size_t:

Electricity will now flow around the dummy battery, following the washer-tipped wire. In this way the four-battery-holder now holds only three, and the voltage it s usually supposed to supply (6 volts) is dropped down to the 4.5 volts you need.

By Stanley B Lippman,Jos e Lajoie,

The subscript operator E Moo read or write the bit at the indexed position As such, we can Barbara lets us use it to test the that value: value of a given bit or to set

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